y = (3t + 1)/p, Where t = 3, and y = 2, what is the value of p?

Firstly, we need to make the unknown variable(p) the subject of the formula. As this is the denominator of a fraction we can multiply both sides of the equation to get rid of the denominator on the right hand side (RHS). This will give us py=3t+1. However, we need p to be on its own so we can divide both sides of the equation by y to remove it from the LHS. This now gives us p=(3t+1)/yAs we can see, t=3 and is multiplied by 3 which will give us 9. Using BIDMAS, we do what is in the brackets of the equation first. 9+1=10 so inside the bracket we have 10. We are given the value of y as 2. So now we know p=10/2 and therefore we know that p=5.

LP
Answered by Louis P. Maths tutor

4046 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How would I make S the subject of the formula in the equation V^2 = U^2 + 2AS


2476 adults watch a cricket match. The ratio men : women is 3 : 1 How many more men than women watch the match?


What is a limit


15 machines work at the same rate, 15 machines can complete an order in 8 hours, however 3 of the machines break down after 6 hours. The other machines continue until the order is complete. In total how many hours does EACH machine work? (3 mark question)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning