Solve the following pair of simultaneous equations; 10x+4y=15, 2x+y=7

So, to solve these equations, you must choose the variable you want to work with, in this case let's go with y. Make sure that you write out every step of your working so it is easy to follow and minimises mistakes. As we are focusing on y, lets re-arrange the second equation to y=7-2x. Now we can just substitute this into the first equation: 10x+4(7-2x)=15. Now we are left with one variable which allows us to find out its value. Expanding the bracket it gives us: 10x+28-8x=15. Tidying it up gives us: 2x=-13, which gives us x=-13/2. Leave it in the fraction form rather than decimal as it is easier to work with. Now, we know the x value, we insert that back into the second equation: 2(-13/2) +y=7, -13+y=7, y=20. To check your answer is correct, put these values into first equation with x and y values: 10(-13/2)+4(20)=15, -65+80=15, 15=15.

JH
Answered by Jung H. Maths tutor

3264 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise this equation and then solve for x) 2x^2 - 3x-2


What are the roots of (2x-5)(x-3) = 0


We have 2 spinners: spinner A and spinner B. Spinner A can land on 2, 3, 5 or 7. Spinner B can land on 2, 3, 4, 5 or 6. Spin both. Win if one spinner lands on odd and the other lands on even. Play game twice, what is the probability of winning both games?


Insert one pair of brackets so that this calculation is correct; 3 x 6 + 5 - 1 = 32


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning