x^2 = 4(x – 3)^2

This is a quadratic equation, which contains terms up to x2. All quadratic equations can be written in the form ax2 + bx + c = 0 where a, b and c are numbers, and a cannot be equal to zero. Expand the brackets: x2 = 4(x2 - 6x + 9). Multiply RHS brackets by 4: x2 = 4x2 - 24x + 36. Collect x's on one side: 3x2 - 24x + 36 = 0. Simplify: x2 - 8x + 12 = 0. Factorise: (x - 6)(x - 2) = 0. The product of x - 6 and x - 2 is 0, so one or both brackets must also be equal to 0, hence x = 6 or x = 2. Alternatively you can use the quadratic formula provided in the formula sheet and substitute the corresponding numbers in, or solve by completing the square.

JW
Answered by Jennifer W. Maths tutor

3591 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the equation (2x+3)/(x-4)-(2x-8)/(2x+1)=1 and give the answer to 2 decimal places


Solve the simultaneous equations y = x + 3 and y = x^2 + 3x


How should I divide up my time during the exam?


Solve simultaneously 2x + 3y = 18 and y = 3x – 5 to find the value of x and y.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning