In a circuit with a thermistor and bulb, what happens to the brightness of the bulb as the temperature increases?
As the temperature increases, the resistance of the thermistor decreases. So the resistance of the whole circuit decreases. Using V=IR, the PD remains constant but resistance has decreased, so current must increase. Using V=IR in just the bulb, the resistance is unchanged, the current has increased so the PD increases. The bulb gets brighter
Related Physics A Level answers
All answers ▸What's the difference between a bayron and a meson?
An ice cube with a small iron ball in its centre is placed in a cup of water. 3.9 x 10-3kg of water in the cup is displaced and the volume of the ice cube is 4.0 x 10-6m3. Ice density: 1000 kg m-3 Iron density: 7800 kg m-3, what is the volume of the iron?
The LHC accelerates protons to a speed of 0.999999991c around a 27km ring. Due to relativistic effects, their mass increases. Given that the magnetic fields used are 8T, calculate this mass. What is the total energy of an LHC beam containing 3e14 protons?
An electron of mass 9.11x10^(-31) is fired from an electron gun at 7x10^6 m/s. What size object will the electron need to interact with in order to diffract?