Solve the following simultaneous equations. x^2 + 2y = 9, y = x + 3

x^2 + 2y = 9y = x + 3
x^2 + 2y = 9x^2 + 2(x+3) = 9x^2 + 2x + 6 = 9x^2 + 2x - 3 = 0(x + 3)(x - 1) = 0x= -3, x = 1
when x = -3y = x + 3y = (-3) + 3y = 0
when x = 1y = x + 3y = (1) + 3y = 4

JF
Answered by John F. Maths tutor

2673 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

3x^2 + 7x - 13 = 0. What is x?


Rearrange the following formula to make x the subject. y=4x-7


Factorise x 2 − x − 12


3x + y = -4; 3x -4y = 6; Solve the simultaneous equations for x and y


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning