Solve the following simultaneous equations. x^2 + 2y = 9, y = x + 3

x^2 + 2y = 9y = x + 3
x^2 + 2y = 9x^2 + 2(x+3) = 9x^2 + 2x + 6 = 9x^2 + 2x - 3 = 0(x + 3)(x - 1) = 0x= -3, x = 1
when x = -3y = x + 3y = (-3) + 3y = 0
when x = 1y = x + 3y = (1) + 3y = 4

Answered by John F. Maths tutor

2339 Views

See similar Maths GCSE tutors
Cookie Preferences