Differentiate y=x^2 from first principles

y=x2dy/dx= Limh-->0( ((x+h)2-x2) / (x+h-x) )dy/dx= Limh-->0( (x2 + 2hx + h2 - x2) / h )dy/dx= Limh-->0( (h2 + 2hx) / h )dy/dx= Limh-->0( h + 2x )dy/dx= Limh-->0( h ) + 2xdy/dx= 2x

Related Maths A Level answers

All answers ▸

How would you differentiate f(x)=3x(2x-1)^2


A) Differentiate ln(x) b) integrate ln(x)


Why does differentiation give us the results that it does?


The curve C has equation (4x^2-y^3+3^2x)=0. The point P (0,1) lies on C: what is the value of dy/dx at P?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences