A 80kg man is hanging from two 1.5m ropes that lie at 60 degrees from the horizontal. What is the tension in each rope required to prevent the man from dropping?
The man is 80kg so the downward force exerted by his weight is 80g (where g is the force of gravity equalling 9.8 Newtons (2dp)). Therefore the upward force exerted by each rope must equal 40g. Using trigonometry Sin(60)= 40g/T where T= the tension in the rope.Rearrange to make T the subject: 40g/Sin(60)= 452.64
DD
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