A 80kg man is hanging from two 1.5m ropes that lie at 60 degrees from the horizontal. What is the tension in each rope required to prevent the man from dropping?
The man is 80kg so the downward force exerted by his weight is 80g (where g is the force of gravity equalling 9.8 Newtons (2dp)). Therefore the upward force exerted by each rope must equal 40g. Using trigonometry Sin(60)= 40g/T where T= the tension in the rope.Rearrange to make T the subject: 40g/Sin(60)= 452.64
DD
Related Physics A Level answers
All answers ▸Newton's Law of Gravitation states: F=GMm/r^2, where G is the gravitational constant (6.67×10−11m^3kg^−1s^−2). Kepler's Third Law, states t^2=kR^3. The mass of the sun is 1.99x10^30kg. Find the value of k and its units
A car moves from rest and accelerates uniformly at 4m/s/s, how far will it have traveled after 10 seconds?
What is electromotive force (emf) and how can the emf of a battery be measured?
What is a stationary wave?