Solve this simultaneous equation: 6x+2y = 26 and 8x + 3y = 32

If 6x + 2y = 26 then 26 - 6x = 2yy = 13 - 3xSo, using the substitution method.... into 8x + 3y = 328x + 3(13 - 3x) = 328x + 39 - 9x = 32-x + 39 = 3232 + x = 39x = 39 - 32 = 7Sub x = 7 into 6x + 2y = 266(7) + 2y = 2642 + 2y = 262y = 26-42 = -16y = -8Check in other equation: 8x + 3y = 328(7) + 3(-8) = 56 - 24 = 32

SW
Answered by Samuel W. Maths tutor

3948 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Write x^2 + 6x - 10 in the form ((x+a)^2)+b?


A quadrilateral has a perimeter of 42cm. Three sides have equal length and the fourth side is longer by 6cm. What is the length of the fourth side?


How do you solve the following simultaneous equations? 5x+6y=3 2x-3y=12


Give the possible values of x when x^2 - 5x + 4 = 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning