Solve the equation 3(x+1) = 21

When solving an equation with brackets, it is often easiest to expand the brackets first.3(x+1) = 21becomes...3x + 3 = 21Now this looks like an equation we know how to solve(minus three from both sides)3x + 3 - 3 = 21 - 3becomes...3x = 18divide both sides by 3...x = 6

JM

Related Maths GCSE answers

All answers ▸

Work out 51% of 400


How do you solve these simultaneous equations? 4x + 5y = 8; 2x + 3y = 5


f(x)=cos(x), g(x)=2+cos(x-1), state g(x) as a vector applied to f(x)


Solve algebraically the simultaneous equations: x^2 + y^2 = 25 and y – 3x = 13