Solve the simultaneous equations 2x + 3y = 6 - 3x and 5x + 6y = 10 - y.

Step 1: First it is best to rearrange the to simultaneous equations to have the unknown variables on one side and the constants on the other: 5x + 3y = 6 and 5x + 7y = 10.Step 2: Next is to notice that both equations share '5x' as a term which allows it to be cancelled out by taking one equation away from the other. We shall take away the equation with smaller y coeffecient from the equation with larger y coeffecient:(5x + 7y) - (5x + 3y) = 4y and 10 - 6 = 4 which gives us: 4y = 4 and such y=1.Step 3: Finally we must solve for x by substituting the value of y=1 into one of the equations:5x + 3 = 6 so 5x = 3. Dividing by 5 gives us x = 3/5 and y=1. (Another step can be added here by substituting both the x and y into the other equation as a form of self-checking: 3 + 7 = 10 which is true.)

FW
Answered by Fraser W. Maths tutor

3847 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The area of a square is 49cm^2. The perimeter of the square is equal to the circumference of a circle. Work out the radius of the circle. Give your answer to 1 decimal place.


Solve the simultaneous equations: 1) 4x - 2y = 28, 2) 4y - 3x = -36.


An arithmetic series is 2,5,8,11... What is the nth term of this sequence?


The circle c has equation x^2+ y^2 = 1. The line l has gradient 3 and intercepts the y axis at the point (0, 1). c and l intersect at two points. Find the co-ordinates of these points.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning