(a) Expand and simplify (x − 3)(x + 5), ..2 marks.. (b) Solve x^2 + 8x − 9 = 0 ..3 marks..

(a) Remember: Multiply each term in the left bracket by every term in the right bracket.(x-3)(x+5) = x2+ 5x - 3x -15.Collecting all of the like terms:= x2+ 2x -15.
(b) Solve x2 + 8x − 9 = 0Remember to put equation in the form ax2 + bx + c = 0. Here, the equation is already in that form.We need to find two numbers to go into the brackets that add to make 8 (b) and also multiply to make -9 (a x c).We find these numbers are 9 and -1. (9 + -1 = 8 and -1 x 9 = -9)So (x+9)(x-1) = 0.Setting each bracket to = 0, we get:x + 9 = 0, or, x -1 = 0So, x = -9 or x = 1.

Answered by Jack W. Maths tutor

8142 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

a)Rearrange the folowing to make m the subject; 4(m-2) = t(5m+3)


Expand and simplify (2x+5)(x^2 + 3x -1)


Complete the square of x^2 + 10x -3


Solve the following simultaneous equations. 2x + 5y = -4. 7x + y = 19


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences