x^2 - y = 14, y - 2 = 6x, solve these equations simultaneously

Make y the sbject of the second eqautiom y=6x+2. substitute this for the y in the first equation.the first equation now looks like x2 -(6x+2)=14. Open the brackets and subtract 14 from both sides. x2 -6x-16=0. Now we can factorise this to (x-8)(x+2)=0. from this we can deduce that x=8 and -2. We still need to find the answer to y since we know y=6x+2 (from first line) We can stustitute our answers to x in this. So When x=8, y= 50. When x=-2, y=-10

Answered by Jai P. Maths tutor

2529 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If f(x) = x^2 - x + 7, find f(3)


Work out the number of green pens in the box. (rest of Q below)


Sketch the curve y = x^2 - 6x + 5, identifying roots and minima/maxima.


A "day return" train ticket is £6.45. A "monthly saver" is £98.50. Sue worked for 18 days last month. She bought a day return ticket each day she worked. A monthly saver ticket is cheaper than 18 day return tickets. How much cheaper?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences