x^2 - y = 14, y - 2 = 6x, solve these equations simultaneously

Make y the sbject of the second eqautiom y=6x+2. substitute this for the y in the first equation.the first equation now looks like x2 -(6x+2)=14. Open the brackets and subtract 14 from both sides. x2 -6x-16=0. Now we can factorise this to (x-8)(x+2)=0. from this we can deduce that x=8 and -2. We still need to find the answer to y since we know y=6x+2 (from first line) We can stustitute our answers to x in this. So When x=8, y= 50. When x=-2, y=-10

Answered by Jai P. Maths tutor

2800 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 3x +4y = 18, and 5x - 2y = 4


Prove algebraically that the square of any odd number is always also an odd number.


Find the solutions to this quadratic equation: 0 = 2x^2 - 5x - 3


Solve the simultaneous equations: x^2+y^2=36 ; x=2y+6


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences