Solve the following simultaneous equations to find x and y.

2x2 - 2y = 282y - 4 = 12x
y - 2 = 6xy = 6x + 2
Substitute y = 6x + 2
2x2 - 2(6x + 2) = 282x2 - 12x - 4 = 282(x2 - 6x - 2) = 28x2 - 6x - 2 = 14x2 - 6x - 16 = 0(x - 8)(x + 2) = 0
if x = 8 then y = 50if x = -2 then y = -10

Answered by Prahlad D. Maths tutor

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