Solve the following simultaneous equations to find x and y.

2x2 - 2y = 282y - 4 = 12x
y - 2 = 6xy = 6x + 2
Substitute y = 6x + 2
2x2 - 2(6x + 2) = 282x2 - 12x - 4 = 282(x2 - 6x - 2) = 28x2 - 6x - 2 = 14x2 - 6x - 16 = 0(x - 8)(x + 2) = 0
if x = 8 then y = 50if x = -2 then y = -10

Answered by Prahlad D. Maths tutor

2307 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 3 red beads and 1 blue bead in a jar. A bead is taken at random from the jar. what is the probability that the bead is blue?


Work out the value of the following:


How to be fully prepared for the exam?


How do you solve the equation '2x + 1 = 5'?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences