Solve the following simultaneous equations to find x and y.

2x2 - 2y = 282y - 4 = 12x
y - 2 = 6xy = 6x + 2
Substitute y = 6x + 2
2x2 - 2(6x + 2) = 282x2 - 12x - 4 = 282(x2 - 6x - 2) = 28x2 - 6x - 2 = 14x2 - 6x - 16 = 0(x - 8)(x + 2) = 0
if x = 8 then y = 50if x = -2 then y = -10

PD
Answered by Prahlad D. Maths tutor

3403 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Write 0.2(54) as a fraction in its simplest form. (Where 0.2(54) = 0.254545454...)


What is BODMAS?


A gym has 275 members. 40% are bronze members. 28% are silver members. The rest are gold members. Work out the number of gold members.


How do you solve simultaneous equations?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning