You will be presented with two equations, both with two unknown values. For example:
8x-2y=19
and
3x=5+y
To begin, we are going to move both unknown terms in the second equation to the same side:
3x-y=5
Then, we are going to multiply this entire equation by 2, in order to have equal y values:
6x-2y=10
At this point, we will subtract the manipulated second equation to the first, so that we cancel out the y values:
2x=9
Now we can find the value of x by dividing by 2:
x=4.5
With this value of x, we can find the value of y through substitution. Putting our value for x into the first equation:
8(4.5)-2y=19
36-2y=19
36=19+2y
17=2y
8.5=y
Having shown this working, you can give the answer on your paper as follows:
x=4.5, y=8.5
Remember you will always need to show your working when doing this in an exam.