Please can you explain E/Z isomers?
1. Assign priority to the four groups attached to the double bond, by adding up their atomic numbers.
2. Work out which are the two highest priority (highest atomic number) - one on each carbon.
3. If these two are on the Zame Zide (same side) of the carbon, then it's Z but if they're on oppositE sides then it's E
JB
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