Work out the value of n, the value of A & the value of B (question given below in correct subscript)

(2x3/2y-1)n = Ax6yB First of all both sides need to be written in the same format so simplify the left hand side. 2n (x3/2)n (y-1)n We are given the power of x is 6 so we can write and equation and solve to find n. x3n/2 = x6 Ignore the x as that is a constant value 3n/2 = 6 so 3n = 12 and n = 4 Now substitute n to find A and B. 24= 16 and y-1x4= y-4 This means n=4, A=16 and B=-4

Answered by Megan L. Maths tutor

3296 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

In triangle ABC, right angled at B, AB = 3 cm and AC = 6 cm. Determine angle BAC and angle ACB.


Solve by factorisation: 2(x^2) - 5x - 12 = 0


Factorise 3x+12


Solve 7x+6 > 1+2x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences