Work out the value of n, the value of A & the value of B (question given below in correct subscript)

(2x^3/2y^-1)ⁿ = Ax⁶y^B First of all both sides need to be written in the same format so simplify the left hand side. 2ⁿ (x^3/2)ⁿ (y^-1)ⁿ We are given the power of x is 6 so we can write and equation and solve to find n. x^3n/2 = x⁶ Ignore the x as that is a constant value 3n/2 = 6 so 3n = 12 and n = 4 Now substitute n to find A and B. 2⁴= 16 and y^-1x4= y^-4 This means n=4, A=16 and B=-4