Radius = 1, therefore diameter = 2Let x be the length of one side of the square.Using Pythagoras,x2 + x2 = 222x2 = 4x = sqrt(2)Area of isosceles triangle = side of square * half side of square= sqrt(2) * sqrt(2)/2= 1Shaded area = area of circle - area of square= π(1)2 - sqrt(2)2 = π - 2 Answer = 1:π-2