The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

We know the perimiter is split into the proportions 3:4:5 therefore by adding 3+4+5 we can work out what fraction of 72cm each side is.Thus 3/(3+4+5) = 3/12 = 1/4 is the fraction of 72 that belongs to the shortest side. This means the shorest side has lenght of 1/4 * 72 = 18cm.We can repeat this to work out the lenght of the other two sides giving the middle sized side to have lenght 4/12 * 72 = 1/3 * 72 = 24cm.And the longest side lenght 5/12 * 72 = 30cm.
We can now draw and label a sketch of the triangle.As it is a right anlged triangle we can use the formular Area = 1/2 * Base * Height. Which gives 24 * 18 * 1/2 = 12 * 18 = 10 * 18 + 2 * 18 = 216cm2

SD
Answered by Sefton d. Maths tutor

11255 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Write x² + 4x -16 = 0 in the form (x+a)² - b = 0. Solve the equation giving your answer in surd form as simply as possible.


Solve x^(2)-x-12


Make h the subject of h-36=(3h+18)/i


A teacher gives her students a maths test and they receive the scores: 4, 4, 7, 3, 9, 10, 5, 8. What was the mean score of the class?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning