Solve the simultaneous equations 3x + y = –4 and 3x – 4y = 6

Rearrange first equation so we can eliminate one variable: y= - 4 -3x We can then plug this into the second equation so we get rid of the y's and just have x's: 3x-4(-3x-4)=6Simplify this: 3x + 12x+16=6 which gives 15x = -10 and then x=-10/15 = -2/3Can plug x back in to any equation to find out y, this gives: y = - 4 -3(-2/3)y= - 4 +2 so y= -2Final answer: x= -2/3 and y= -2

AC
Answered by Anushka C. Maths tutor

3499 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following set of simultaneous equations: (eq.1) x + 3y = 10, (eq.2) 2x + y = 5


Solve 6x^2+8x-8 = 0 using factorisation.


What is 12x^6 / 7 divided by 4x^2 / 5 ?


When do I use the sin rule and when do I use the cosine rule?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning