A satellite is in orbit of the Earth, and moves at a constant orbital speed of 3055.5m/s. If it is at an altitude of 35786km, calculate the time period for a complete cycle, giving your answer in hours. Answer should be given in in 3 significant figures.

Orbital Speed = [2Π(Orbital Radius)]/Time Period
3055.5m/s = 10999.8km/h
therefore:
10999.8km/h = [2Π(35786km)]/TT = [2Π(35786km)]/(10999.8km/h)T = 20.4 hours

Related Physics GCSE answers

All answers ▸

Describe the transfers of energy occurring when a ball is thrown vertically up in the air and falls back down to Earth, assuming there is no friction from the air.


What is meant by terminal velocity?


Why does a change in depth in water give a far greater difference in pressure than the same change in height in air?


Explain why evaporation cools a liquid.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences