A satellite is in orbit of the Earth, and moves at a constant orbital speed of 3055.5m/s. If it is at an altitude of 35786km, calculate the time period for a complete cycle, giving your answer in hours. Answer should be given in in 3 significant figures.
Orbital Speed = [2Π(Orbital Radius)]/Time Period
3055.5m/s = 10999.8km/h
therefore:
10999.8km/h = [2Π(35786km)]/TT = [2Π(35786km)]/(10999.8km/h)T = 20.4 hours
Related Physics GCSE answers
All answers ▸Calculate the acceleration of particle thats velocity changes from 20ms^-1 to 40ms^-1 in 5 seconds, assuming its constant.
Explain the difference between energy and power.
What's the difference between distance and displacement
I don't understand acceleration and how something can accelerate without speeding up.