A linear sequence starts a + 2b, a + 6b, a + 10b … The 2nd term has value 8 The 5th term has value 44 Work out the values of a and b.

5th Term is a+18b=442nd term is a+ 6b=8subtract the two equations from eachother to get 12b=36 rearrange so that b=36/12=3 substitute b=3 into any of the above equations to get a; a=8-(6x3) = -10 so a=-10 and b=3

Answered by Malini P. Maths tutor

2788 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify (6x - 2y)(3x - 7y)


Factorise fully 6xy + 3y


2x + 7 = 13 - 2x. What is the value of x?


Rationalise the denominator of 2/(3-sqrt(2)).


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences