Find dy/dx, given that y=(3x+1)/(2x+1)
Since the equation for y is given in the format y=u/v, the use of the quotient rule is the easiest way to find the differential of this equation. The quotient rule states, (vu'-uv')/v^2 is equal to the differential of u/vIn this situation u=3x+1 and v=2x+1. The first step to take would be to differentiate the individual parts of the equation so, u'=3 and v'=2.These 4 values can then be put into the quotient rule in order to reach the result of the differential. dy/dx=(3(2x+1)-2(3x+1))/(2x+1)^2, which can be simplified down to dy/dx=1/(2x+1)^2
Related Maths A Level answers
All answers ▸What are the stationary points of the curve (1/3)x^3 - 2x^2 + 3x + 2 and what is the nature of each stationary point.
How would you differentiate ln(sin(3x))?
a) Solve the following equation by completing the square: x^(2)+ 6x + 1= 0. b) Solve the following equation by factorisation: x^(2) - 4x - 5 = 0 c) Solve the following quadratic inequality: x^(2) - 4x - 5 < 0 (hint use your answer to part b)
How do I remember what trig functions differentiate to?