Solve the Simultaneous equations x^2 + y^2 =29, y-x=3.

y=x+3, Substitute into equation 1 : (x^2) + (x+3)^2 = 29Expand the Brackets : (x^2) + (x^2 + 6x + 9) = 29Collect like terms : 2x^2 + 6x - 20 = 0Take out a factor of two : x^2 +3x -10 = 0Factorise : (x-2)(x+5) = 0Solve for x: x=2 or x=-5when x=2: Y=8,when x=-5: Y=-5Check Values confirm: They DO ! ! WOop!

TM
Answered by Theo M. Maths tutor

3036 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 3x + 10 = 10(2x-5)


Solve the simultaneous equations x + y = 3 and x^2 + y^2 = 5


Solve x^2 - 7x > -6


How do I factorise and solve 2x^2+4x-6=0?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences