Solve the Simultaneous equations x^2 + y^2 =29, y-x=3.

y=x+3, Substitute into equation 1 : (x^2) + (x+3)^2 = 29Expand the Brackets : (x^2) + (x^2 + 6x + 9) = 29Collect like terms : 2x^2 + 6x - 20 = 0Take out a factor of two : x^2 +3x -10 = 0Factorise : (x-2)(x+5) = 0Solve for x: x=2 or x=-5when x=2: Y=8,when x=-5: Y=-5Check Values confirm: They DO ! ! WOop!

Answered by Theo M. Maths tutor

2716 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the equation 3x^2+2x-3=3.


(2x+3)^2


Rectangle A has a length of 3y cm and a width of 2x cm. Rectangle B has a length of (y + 4)cm and a width of (x + 6)cm. Rectangle A has a perimeter of 94cm and Rectangle B has a perimeter of 56cm. Solve x and y and calculate the areas of each rectangle.


Rearrange to make p the subject. C + 5 p = a ( C – p )


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences