Find the turning points on the curve with the equation y=x^4-12x^2

y = x^4 - 12x^2
dy/dx = 4x^3 - 24x
The turning points are where dy/dx = 0
4x^3 - 24x =0
x(4x^2 - 24) = 0 Therefore one of the turning points is at x = 0
4x^2 - 24 = 0
4x^2 = 24
x^2 = 6
x = +/- √6
Substitute the x coordinates back into the original equation to find y
The final coordinates are (0,0), (√6,-36) and (-√6,-36)

Related Maths A Level answers

All answers ▸

Differentiate y = √(1 + 3x²) with respect to x


give the coordinates of the stationary points of the curve y = x^4 - 4x^3 + 27 and state with reason if they are minumum, maximum, or points of inflection.


How can I remember how to differentiate and integrate cos and sin?


How to factorise 6x^2-11x-10?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences