find dy/dx when y=x^3 + sin2x
so this question is asking you to differentiate x3 + sin2xwe know that xn differentiates do nxn-1, so using that x3 will differentiate to 3x2we know that sinx differentiates to cosx and 2x differentiates to 2, so sin2x (by chain rule) differentiates to 2cos2xthen adding them, we get dy/dx = 3x2+2cos2x
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