Find the x values for stationary points in the curve y=3sin(2x) for 0<x<180
Firstly we differentiate the equation y=3sin(2x) w.r.t. x.By using the chain rule, we find the dy/dx=6cos(2x)Since a stationary point in the curve is a point where the gradient is 0, we can find them by finding the x values for when dy/dx=0.Therefore, 6cos(2x)=0cos(2x)=02x= cos-1(0) since cos-1(0)=90, 270 x=45, 135
Related Maths A Level answers
All answers ▸A curve has equation y = e^x + 10sin(4x), find the value of the second derivative of this equation at the point x = pi/4.
integrate xsin(x)
A stone, of mass m, falls vertically downwards under gravity through still water. At time t, the stone has speed v and it experiences a resistance force of magnitude lmv, where l is a constant.
Find the antiderivative of the function f(x)=(6^x)+1