Calculate the volume obtained when rotating the curve y=x^2 360 degrees around the x axis for 0<x<2

I haven't yet figured out how to write in proper mathematical notation on here, and my drawing pad is yet to arrive, so please forgive the formatFirst, the formula for the volume of revolution is V= pi * the integral of (y)^2 dxIn this case it means V = pi * integral (x^4)dx between 0<x<2integrating x^4 gives 0.2 x^5 as we reverse the process of bringing down the power and multiplying, henceV= pi * [0.2 x^5] between 0<x<2Substitute values givesV=pi*(0.22^5-0.20)V=pi0.232V=6.4*pior V=20.106....

Related Maths A Level answers

All answers ▸

Find the equation of the tangent to the curve x^3+yx^2=1 at the point (1,0).


Differentiate y = 7(x)^2 + cos(x)sin(x)


Express 9^(3x + 1) in the form 3^y , giving y in the form ax + b, where a and b are constants.


Solve the ODE y' = -x/y.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences