Calculate the volume obtained when rotating the curve y=x^2 360 degrees around the x axis for 0<x<2
I haven't yet figured out how to write in proper mathematical notation on here, and my drawing pad is yet to arrive, so please forgive the formatFirst, the formula for the volume of revolution is V= pi * the integral of (y)^2 dxIn this case it means V = pi * integral (x^4)dx between 0<x<2integrating x^4 gives 0.2 x^5 as we reverse the process of bringing down the power and multiplying, henceV= pi * [0.2 x^5] between 0<x<2Substitute values givesV=pi*(0.22^5-0.20)V=pi0.232V=6.4*pior V=20.106....
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