Write x^2 + 6x - 10 in the form ((x+a)^2)+b?

To find the value of a divide the coeffecient of x. Here this would be 6/2 which = 3. If we were to expand (x + 3)^2 + b this would give us:x^2 + 3x +3x + 3^2 +b which simplifies to x^2 + 6x + 3^2 + b. If we compare the coeffecients of this with the given quadratic, we can see the constant term is 3^2 + b = - 10If we rearrange this we can see b = -19Therefore x^2 + 6x - 10 in the form ((x+a)^2)+b is (x + 3)^2 - 19.The b is always equal to a^2 - [constant term of the quadratic].

Answered by Gunalini G. Maths tutor

12712 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Could you explain ratios to me?


If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?


Make x the subject of 5(x-3) = y(4-3x)


Q) The equation of a curve is y=(x+4)^2+7. Find the co-ordinates of the turning point


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences