Given y=(1+x^3)^0.5, find dy/dx.

In order to solve this question, we need to use the chain rule when differentiating. The chain rule formula is dy/dx= (dy/du)(du/dx). Let u=1+x3Differentiating with respect to x gives du/dx=3x2We now have y=u0.5Differentiating with respect to u gives dy/du=0.5u-0.5=0.5(1+x3)-0.5Therefore dy/dx= (dy/du)(du/dx)= 0.5(1+x3)-0.5*(3x2)= 1.5x2*(1+x3)-0.5

RM
Answered by Rebecca M. Maths tutor

5186 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Express 6cos(2x)+sin(x) in terms of sin(x). Hence solve the equation 6cos(2x) + sin(x) = 0, for 0° <= x <= 360°.


How do you find stationary points of an equation, eg. y=x^2+3x+2


How do i know where a stationary point is and what type of stationary point it is?


A curve has the equation y=sin(x)cos(x), find the gradient of this curve when x = pi. (4 marks)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences