Given y=(1+x^3)^0.5, find dy/dx.

In order to solve this question, we need to use the chain rule when differentiating. The chain rule formula is dy/dx= (dy/du)(du/dx). Let u=1+x3Differentiating with respect to x gives du/dx=3x2We now have y=u0.5Differentiating with respect to u gives dy/du=0.5u-0.5=0.5(1+x3)-0.5Therefore dy/dx= (dy/du)(du/dx)= 0.5(1+x3)-0.5*(3x2)= 1.5x2*(1+x3)-0.5

RM
Answered by Rebecca M. Maths tutor

5361 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Show that tan(x) + cot(x) = 2cosec(2x)


A block of mass 5 kg is being pushed over level ground by rod at 60 degrees to horizontal with force 40 N with acc. 1.5 what is the frictional force of the surface and draw a diagram with the forces acting on the block


∫2x(x+2)^(1/2) dx evaluated from 0->2


How does integration work?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences