Solve the following simultaneous equations to give a value for both x and y: 3x+3y=9 and 2x+3y=5

  1. Subtract the bottom equation from the top equation to get 3x-2x=9-5 (you don't see no y values in this equation as the y's have disappeared and cancelled eachother out as 3y-3y=0)2) So 3x-2x=9-5 equals 1x=4 (which is the same as x=4)3) Now we know x=4, substitute this back into one of the equations to find y, shown below: 3x+3y=9 with x substituted in becomes 3(4)+3y=9 which is equal to 12+3y=94) 12+3y=9, bring the +12 across the equals sign to become -12, giving you 3y=9-12 so 3y=-35) If 3y=-3, divide both sides by 3 to give y=-1 6) So the solution is: x = 4, y = -1 which are your two answers to the simultaneous equation :)
Answered by Amy F. Maths tutor

2606 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Using a method that is not factorisation, solve the equation (x^2) + 3x -4 = 0. Hence, sketch the curve produced by the equation


Show that 12 cos 30° - 2 tan 60° can be written in the form root (k) where k is an integer.


Solve the simultaneous equation: 2x + 3y = 6, 3x + 2y = 5.


What exactly is pi?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences