Solve the simultaneous equation: 3x+2y=8 and 2x+5y=-2

3x+2y=8 (1)2x+5y=-2 (2)So you need to have a common multiple of either x or y in this example I’ll equate the x of both equations so I’ll multiply (1) by 2 and (2) by 3 2( 3x+2y=8). 6x+4y=16 (3).3(2x+5y=-2) 6x+15y=-6 (4)Subtract equation (4) by (3) 6x+15y=-6 -(6x+4y=16)0x+11y=-22y=-2 substitute your value of y into either equation (1) or (2) 3x+2y=83x+2(-2)=83x-4=83x=12x=4double check your answers for x and y into equation (2) 2x+5y=-22(4)+5(-2)=-28-10=-2 so x=4 and y=-2

RD
Answered by Rabia D. Maths tutor

5314 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How to solve a quadratic by factorisation?


Sketching a quadratic


Steve wants to put a hedge along one side of his garden. He needs to buy 27 plants for the hedge. Each plant costs £5.54 Steve has £150 to spend on plants for the hedge. Does Steve have enough money to buy all the plants he needs?


Write the number 0.000000001 in standard form.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning