Complete the square for the following equation: 2x^2+6x-3=0
2x2+6x-3=0To begin, we need to make sure x2 is by itself, meaning that we divide the whole equation by 2. So from here we get (2x2+6x-3=0) / 2 = x2+3x-3/2=0. Now as we have got the x2 on its own, we can now fully complete the square by using: 2[(x+3/2)2-3/2 - ...] = 0. Now the ... stands for a value that has come about from completing the square. And the value is as simple as (-3/2)2 = 9/4. So the correct equation is 2[(x+3/2)2-3/2-9/4]=0. So the correct equation is 2[(x+3/2)2-15/4]=0. However, to finish the equation, we must multiply the entirety of it by 2, and then we have fully completed the square. So therefore we get 2(x+3/2)2-15/2=0.
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