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Find the first derivative of f(x). f(x) = ln(3x^2+2x+1)

The differential of a natural log function gives a fraction where the numerator is the first derivative of what we are taking the natural log of and the denominator is what we are taking the natural log of. In this case, the numerator would be 6x+2. The denominator would be 3x^2+2x+1.

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Find the first derivative of f(x). f(x) = ln(3x^2+2x+1)

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