Solve the following simultaneous equations: 2x - 3y = 16, x + 2y = -6

First we label the two equations as (1) and (2):2x - 3y = 16 (1)x + 2y = -6 (2)We want both equations to have the same number before one of the variables so the easiest way is to multiply equation (2) by two to give an equation we'll label (3):2x + 4y = -6 (3)Now we can do (1) - (3) to cancel out the value of x: (1)-(3) : -7y = 28, which can be solved to give y = -4. Now to get the value of x we substitute this y into one of the original equations, for example (2), giving: x - 8 = -6 which can be solved to give x = 2.So our final answer is x = 2, y = -4.