Solve the following simultaneous equations: 3x + y = 11, 2x + y = 8

first: look at the 2 equations and see if there are any matching coefficients. eg the same number before x or y in both of the equations. in these examples both y values have the coefficient 1. second: either add or subtract the 2 equations to remove the y values. in this case need to do equation 1 - equation 2 in order for y to equal 0. so (3x + y = 11) - (2x +y = 8) = x = 3 - this is the x value of the equations third: find the y value by substituting the known x value (3) into one of the simultaneous equations = 2(3) + y = 8 6 +y = 8 y = 2 - this is the y value fourth: you can check you have the right values by substituting them into one of the equations and seeing if it works. eg 3(3) + 2 = 11 9+2 = 11 11 = 11

RS
Answered by Rebecca S. Maths tutor

2842 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the quadratic equation: 5x2+8x+2


How should I calculate the values of a and b when a(4x+12) is equivalent to 2x+36b?


How do you turn 0.11111... (recurring) into a fraction


A is the point with coordinates (1, 3) B is the point with coordinates (–2, –1) The line L has equation 3y = 4 – 2x Is line L parallel to AB?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning