Find the magnitude of the force on an electron that is travelling with velocity 2 x 10^4 ms^(-1) in the x direction through a uniform magnetic field of strength 2T in the y direction.
This question tells us we only need to consider the magnitude of the force, and since the magnetic field and electron's velocity are perpendicular, we can simply use the equation
F = Bqv.
We have B = 2 T, q = 1.6 x 10-19 C (the charge of an electron) and v = 2 x 104 ms-1.
Substituting these values into the equation gives
F = 2 * (1.6 x 10-19 ) * (2 x 104) = 6.4 x 10-15 N (Remember your units!)
SH
Related Physics A Level answers
All answers ▸Show that the orbital period of a satellite is given by T^2=(4pi^2r^3)/(GM) where r is the orbital radius, G is the gravitational constant and M is the mass of the Earth. Then find the orbital radius of a geostationary satellite.
A conical pendulum is a mass suspended from a point that traces out a horizontal circle. By balancing the weight with the tension in the string, determine the speed of the bob.
A ball is dropped from rest at a height of 2 metres. Assuming acceleration due to gravity (g) is 10m/s^2 calculate the velocity of the ball just before it hits the floor.
An electron is traveling at a velocity of 500m/s perpendicular to a uniform magnetic field. A force of magnitude 4.32 x10^(-16) N is acting on the electron, what is the magnetic flux density of the field?