Find the magnitude of the force on an electron that is travelling with velocity 2 x 10^4 ms^(-1) in the x direction through a uniform magnetic field of strength 2T in the y direction.
This question tells us we only need to consider the magnitude of the force, and since the magnetic field and electron's velocity are perpendicular, we can simply use the equation
F = Bqv.
We have B = 2 T, q = 1.6 x 10-19 C (the charge of an electron) and v = 2 x 104 ms-1.
Substituting these values into the equation gives
F = 2 * (1.6 x 10-19 ) * (2 x 104) = 6.4 x 10-15 N (Remember your units!)
SH
Related Physics A Level answers
All answers ▸Given the Earth orbits the Sun at a distance of 1.49*10^11m with Me = 5.97*10^24kg and Msolar = 1.99*10^30, what is the gravitational force between the Earth and Sun?
How do I calculate the hydrostatic pressure?
An electron and a proton are in any electric field E=5x10^2 V/m. What is their speed 1.0 cm after being released?
What is the de Broglie wavelength? Why do we care?