A curve is defined by the parametric equations x = 3^(-t) + 1, y = 2 x 2^(t). Show that dy\dx = -2 x 3^(2t).

Write 3^(t) as an expression involving x : We can rewrite x = 3^(-t) + 1 as x - 1 = 3^(-t) ; equivalently, 3^(t) = (x-1)^(-1). Substitute this expression into y, to write y in terms of x: y = 2 x 3^(t) = 2 x (x-1)^(-1). Differentiate y with respect to x, using the power rule:dy\dx = -2(x-1)^(-2). Substitute in the expression for 3^(t):dy\dx = -2(x-1)^(-2) = -2 x (3^(t))^(2) = -2 x 3^(2t)

MK
Answered by Maleeha K. Maths tutor

3412 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the coefficient of the x^3 term in the binomial expansion of (2x+(1/3x^2))^9


Can you show me why the integral of 1/x is the natural log of x?


The equation kx^2+4kx+5=0, where a is a constant, has no real roots. Find the range of possible values of k.


What marks do I need to achieve an A* grade in A-level Maths?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning