A curve is defined by the parametric equations x = 3^(-t) + 1, y = 2 x 2^(t). Show that dy\dx = -2 x 3^(2t).

Write 3^(t) as an expression involving x : We can rewrite x = 3^(-t) + 1 as x - 1 = 3^(-t) ; equivalently, 3^(t) = (x-1)^(-1). Substitute this expression into y, to write y in terms of x: y = 2 x 3^(t) = 2 x (x-1)^(-1). Differentiate y with respect to x, using the power rule:dy\dx = -2(x-1)^(-2). Substitute in the expression for 3^(t):dy\dx = -2(x-1)^(-2) = -2 x (3^(t))^(2) = -2 x 3^(2t)

Answered by Maleeha K. Maths tutor

2798 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

a) Differentiate and b) integrate f(x)=xcos(2x) with respect to x


A curve has the equation y = 2x cos(3x) + (3x^2-4) sin(3x). Find the derivative in the form (mx^2 + n) cos(3x)


Find the equation of the line that is perpendicular to the line 3x+5y=7 and passes through point (-2,-3) in the form px+qy+r=0


Solve the equation 3 sin^2 theta = 4 cos theta − 1 for 0 ≤ theta ≤ 360


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences