Work out the point at which the line y = x^2 + 4x + 4 hits the y-axis and the x value of its turning point.

To work out the point at which the line hits the y axis, we need to know where x = 0. In order to do this, we need to set x = 0, and so we are left with x = 4.
To find the turning point, we need to differentiate the equation. We need to find the derivative of y with respects to the derivative to x. To do this, we remove the x power and -1 times the multiple of x, multiplying the value by its original power i.e. x would go to 1 and x^2 would go to 2x. In this case, we would get dy/dx = 2x + 4, and since we know that the turnig point is the point on a graph where the curve's gradient is 0, we set dy/dx = 0. Solving and rearranging for x, we get 2x = 4, and x = -2.

EC
Answered by Ethan C. Maths tutor

2703 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If a right angled triangle has its longest side 7cm and another side is 4cm then how long is the other side of the triangle? Show your working


Solve the simultaneous equations 3x + y = –4 and 3x – 4y = 6


Write the number 0.000000001 in standard form.


Solve algebraically for a and b: 6a+b=16, 5a-2b=19


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences