Differentiate the equation y = x^2 + 3x + 1 with respect to x.

A simple way to differentiate an equation with respect to x is to reduce each x components power by one and multiply each x component by their original power.

Looking at the equation y = x^2 + 3x + 1, the component x^2 will be reduced from a power of 2 to a power of 1 and multiplied by its original power 2 to give 2x. The component 3x is reduced from a power of 1 to a power of zero and multiplied by its original power of 1 to give 3. As 1 is a constant and not an x component it dissapears in the differentiated eqution.

This therefore gives an answer of dy/dx = 2x + 3.

Answered by Jake B. Maths tutor

4368 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Consider the functions f and g where f (x) = 3x − 5 and g (x) = x − 2 . (a) Find the inverse function, f^−1 . (b) Given that g^−1(x) = x + 2 , find (g^−1 o f )(x) . (c) Given also that (f^−1 o g)(x) = (x + 3)/3 , solve (f^−1 o g)(x) = (g^−1 o f)(x)


Integrate the function x(2x+5)^0.5


Explain why for any constant a, if y = a^x then dy/dx = a^x(ln(a))


The point P lies on the curve C: y=f(x) where f(x)=x^3-2x^2+6x-12 and has x coordinate 1. Find the equation of the line normal to C which passes through P.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences