Let y = (4x^2 + 3)^4. Find dy/dx.

32x(4x^2 + 3)^3

Related Further Mathematics GCSE answers

All answers ▸

Given f(x)= 8 − x^2, solve f(3x) = -28


Expand (2x+3)^4


y=(6x^9 +x^8)/(2x^4), work out the value of d^2y/dx^2 when x=0.5


Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences