Solve the simultaneous equations: x^2-y=16 and 2y-4=14x

Equations: (1) x^2-y=16 and (2) 2y-4=14xRearrange (2) to give y:2y-4=14x(+4) 2y=14x+4(/2) y=7x+2call the new equation (3) y=7x+2Put (3) into (1):x^2-(7x+2)=16(expand) x^2-7x-2=16(-16) x^2-7x-18=0(Factorise) (x-9)(x+2)=0so x=9 or x=-2Substitute x values into (3):when x=9:y=7(9)+2y=63+2y=65or when x=-2y=7(-2)+2y=-14+2y=-12So, either x=9 & y=65 or x=-2 & y=-12

HC
Answered by Hollie C. Maths tutor

3585 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

factorise: 3x^2+13x-30


There are 5 white socks and 3 black socks in a draw. Steven takes out 2 at random. Work out the probability that Steven takes out 2 socks of the same colour.


Solve the simultaneous equations 3x + 2y = 4, 4x + 5y = 17


You are given two equations: 3y-2x=11 and y+x=12. By solving simultaneously, what is the value of x and the value of y.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences