Solve the simultaneous equations: x^2-y=16 and 2y-4=14x

Equations: (1) x^2-y=16 and (2) 2y-4=14xRearrange (2) to give y:2y-4=14x(+4) 2y=14x+4(/2) y=7x+2call the new equation (3) y=7x+2Put (3) into (1):x^2-(7x+2)=16(expand) x^2-7x-2=16(-16) x^2-7x-18=0(Factorise) (x-9)(x+2)=0so x=9 or x=-2Substitute x values into (3):when x=9:y=7(9)+2y=63+2y=65or when x=-2y=7(-2)+2y=-14+2y=-12So, either x=9 & y=65 or x=-2 & y=-12

Answered by Hollie C. Maths tutor

3358 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A right angled triangle has two short sides of lengths 5cm and 12cm respectively. What is the length of the third side?


Solve (6/x-2)-(2/x+3)=1


How do you find the turning point of a quadratic equation?


Solve the following simultaneous equations: 6j+4k=40; 7j-3k=-7


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences