Differentiate y = arcsin(x) with respect to x

y = arcsin(x) implies sin(y) = x
Differentiating with respect to x gives: cos(y)*dy/dx = 1So: dy/dx = 1/cos(y)
Noting that cos(y) = sqrt(1 - sin^2(y)): dy/dx = 1/sqrt(1 - sin^2(y)) = 1/sqrt(1 - x^2)

Answered by Maths tutor

4061 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

two balls of similar size masses m and 2m are moving at speeds u and 2u along a frictionless plane, they collide head on and are reflected, assuming that the coefficient of restitution of this collision is 1, what the speeds are afterwards in u


Differentiate y=x^3*(x^2+1)


Given a quadratic equation, how do I find the coordinates of the stationary point?


Find dy/dx if y= sinx/2x+1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning