Differentiate y = arcsin(x) with respect to x
y = arcsin(x) implies sin(y) = x
Differentiating with respect to x gives: cos(y)*dy/dx = 1So: dy/dx = 1/cos(y)
Noting that cos(y) = sqrt(1 - sin^2(y)): dy/dx = 1/sqrt(1 - sin^2(y)) = 1/sqrt(1 - x^2)
Related Maths A Level answers
All answers ▸Solving 2tan(x) - 3sin(x) = 0 for -pi ≤ x < pi
The line AB has equation 5x + 3y + 3 = 0. The point with coordinates (2k + 3, 4 -3k) lies on the line AB. How do you find the value of k.
A cannonball is fired at an angle of 30 degrees and a velocity of 16 m/s. How long does it take (to 2 significant figures) for the cannonball to reach the ground?
Solve simultaneously: x + y + 3 = 0 and y = 2x^2 +3x - 1