Differentiate y = arcsin(x) with respect to x

y = arcsin(x) implies sin(y) = x
Differentiating with respect to x gives: cos(y)*dy/dx = 1So: dy/dx = 1/cos(y)
Noting that cos(y) = sqrt(1 - sin^2(y)): dy/dx = 1/sqrt(1 - sin^2(y)) = 1/sqrt(1 - x^2)

Related Maths A Level answers

All answers ▸

Use logarithms to solve 9^x=15


How do you prove two straight lines intersect?


Find dy/dx in terms of t for the curve given by the parametric equations x = tan(t) , y = sec(t) for -pi/2<t<pi/2.


How do you differentiate y=x^x?