(x+6) and (x+5) are the length and width, respectively, of a rectangle with area 20. Calculate the width of the rectangle.

(x+6)(x+5)=20. x2 + 11x +30=20. x2+ 11x + 10 = 0. (x+10)(x+1)=0 . x=-1 and x=-10. width= -10+5=-5 (invalid solution). width =-1+5= 4. Checking through: (-1+6)*(-1+5)=20.

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations. x^2 + 2y = 9, y = x + 3


James has a short drive to his garage which he wishes to pave with a single layer of bricks. If his square drive has side length 2m and James buys the bricks in stacks of 10 with each brick being 0.2m long and half as wide how many stacks must James buy?


How do you factorise x^2 + 3x + 2?


Solve the following pair of simultaneous equations: 1. 3x + 2y = 9 2. 6x + 5y = 21


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences