(x+6) and (x+5) are the length and width, respectively, of a rectangle with area 20. Calculate the width of the rectangle.

(x+6)(x+5)=20. x2 + 11x +30=20. x2+ 11x + 10 = 0. (x+10)(x+1)=0 . x=-1 and x=-10. width= -10+5=-5 (invalid solution). width =-1+5= 4. Checking through: (-1+6)*(-1+5)=20.

Answered by Maths tutor

2832 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Given that y is directly proportional to square root of x and that y = 20 when x = 49 find an expression to represent x and y.


Find the value(s) of x which satisfies the equation 3x^2 + 6x + 3 = 0


Expand and simplify (6x+9)(4x+7)


The circle c has equation x^2+y^2 = 1 . The line l has gradient 3 and intercepts the y axis at the point (0, 1). c and l intersect at two points. Find the co-ordinates of these points.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences