Solve the simultaneous equations: 5x + y =21 and x - 3y = 9.

Rearrange x - 3y = 9 to make x the subject by adding 3y to both sides of the equation, giving x = 9 + 3y. Substitute the value of "x" in the second equation for "9 + 3y", giving: 5(9 + 3y) + y = 21. Multiply out the brackets to give 45 + 15y + y = 21. Add together like terms: 45 + 16y = 21, then subtract 45 from both sides: 16y = -24, and then divide both sides by 16 to give the value of y = -1.5.
Then substitute the value of y into equation "5x + y = 21" which gives 5x - 1.5 = 21. Add 1.5 to both sides to give 5x = 22.5, and then divide both sides by 5 to give the value of x: x = 4.5.

RS
Answered by Rebecca S. Maths tutor

16083 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

P is a point on a circle with the equation x^2 + y^2 = 45. P has x-coordinate 3 and is above the x axis. Work out the equation of the tangent to the circle at point P.


Completing the Square


Solve 8x + 9y = 3 and x + y = 0.


Anouk, Beth and Carlin share £48 between them. Beth gets 3/8 of the money. Anouk and Carlin share the remaining money between them, by the ratio 3:2. How much money does Carlin get?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning