A particle of mass 5kg is moving in circular motion with a time period of 2 seconds. The radius of the circle is 10m. What is the centripetal force on the particle

The angular velocity is equal to 2 times pi divided by the time period. So we have an angular velocity of pi radians per second. The centripetal force is given by mass times the radius times the angular velocity squared so, 5x10xpi=50pi which is approximately 157.08N.

Answered by Physics tutor

1853 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A ball is thrown downwards from a height of 10m with speed of 5m/s, assuming g=10m/s^2, calculate the final velocity of the ball when it hits the ground


A ball is released from height h w.r.t. the ground. Draw a qualitative height versus time diagram of the ball bouncing in a non-ideal case.


Compare and contrast elastic and inelastic collisions


What is the Doppler Effect?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning