write the vector equation of a line passing through (1,-1,2) and (2,2,2).

The vector from (1,-1,2) to (2,2,2) will have direction (2,2,2)-(1,-1,2) which is (1,3,0) so the vector equation is r =(1,-1,2) + s(1,3,0) where s is a scalar.

Answered by Maths tutor

2537 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

a) Solve the following equation by completing the square: x^(2)+ 6x + 1= 0. b) Solve the following equation by factorisation: x^(2) - 4x - 5 = 0 c) Solve the following quadratic inequality: x^(2) - 4x - 5 < 0 (hint use your answer to part b)


Find the exact solution to ln(2y+5) = 2 + ln(4-y)


How to differentiate y = xcos(x)


Differentiate y= 2^x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning