Simplify the boolean expression ¬(A.B)+A.
¬(A.B)+A -- given in question. =(¬A+¬B)+A -- using De Morgan's Law. =¬A+¬B+A -- can remove the brackets. =1+¬B -- using identity ¬A+A = 1.=1 -- using identity 1 + anything = 1.
¬(A.B)+A -- given in question. =(¬A+¬B)+A -- using De Morgan's Law. =¬A+¬B+A -- can remove the brackets. =1+¬B -- using identity ¬A+A = 1.=1 -- using identity 1 + anything = 1.
