Solve the simultaneous equations: 5x + y = 21, x - 3y = 9

Two equations 1) 5x + y = 21, 2) x - 3y = 9. Eliminate x or y by manipulating equations 1 or 2. Equation 3 = equation 2 x 5 = 5(x-3y) = 5(9) 3) 5x - 15y = 45. Equations 3 & 1 both have 5x's so we can subtract equation 1 from equation 3 to get a new equation with only y's, no x's.(5 - 5)x + (-15 - 1)y = 45 - 21, which evaluates to -16y = 24, giving y = -24/16 = -3/2 = -1.5. This value of y satisfies equations 1 & 2. Substitute this value into 1 or 2 to find x: 5x + (-1.5) = 21, 5x = 21 - -1.5 = 22.5, x = 4.5. So x = 4.5 & y = -1.5 are solutions to the pair of simultaneous equations.

JL
Answered by Jason L. Maths tutor

3393 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is the sum of the first 100 numbers of the following sequence- 4,12,36, 108, .........


Explain the general formula for a sraight line?


The equation of a curve is y = (x + 3)^2 + 5. Find the coordinates of the turning point.


How do you simplify (3x-3)/(x-1)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning