Fully factorise the expression 14x^2y - 28xy^2

First take out a factor of x to give x(14xy - 28y2)Next take out a factor of y to give xy(14x - 28y)Finally take out a factor of 7 to give 7xy(2x - 4y)

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2x + y = 10 and 4y - 5x = 1, solve for x and y.


Solve by factorisation. 2x(^2)+5x-12=0


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