Find the area under the curve y=xexp(-x)

first recognise ‘area under’ = integrationfunction is a product so by partsset x=u; exp(-x)=dv/dx integral(udv/dx)=uv-integral(vdu/dx)
du/dx =1; v=-exp(-x)ans=(x.-exp(-x))-integral(1.exp(-x)dx)ans=-xexp(-x)+exp(-x)+C

Answered by Maths tutor

2718 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate xe^2


Find the coordinates of the stationary point of y = x^2 + x - 2


Where do the graphs of y=3x-2 and y=x^2+4x-8 meet?


Given that y = 4x^3 – 5/(x^2) , x not equal to 0, find in their simplest form (a) dy/dx, and (b) integral of y with respect to x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences