Find the area under the curve y=xexp(-x)

first recognise ‘area under’ = integrationfunction is a product so by partsset x=u; exp(-x)=dv/dx integral(udv/dx)=uv-integral(vdu/dx)
du/dx =1; v=-exp(-x)ans=(x.-exp(-x))-integral(1.exp(-x)dx)ans=-xexp(-x)+exp(-x)+C

Answered by Maths tutor

3039 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrating (e^x)sin(x)


The expansion of (1+x)^4 is 1 + 4x +nx^2 + 4x^3 + x^4. Find the value of n. Hence Find the integral of (1+√y)^4 between the values 1 and 0 (one top, zero bottom).


How do I calculate where a function is increasing/decreasing?


Show how you can rewrite (x+1)(x-2)(x+3) into the form of ax^3 + bx^2 + cx + d


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning